Gravity
is a force that acts only on objects with mass. As you
know from Newton's 2nd Law, forces cause objects to
accelerate or change their velocity with time. Acceleration
can be expressed by the formula:
(2)
where
a is acceleration, D v is the change in velocity and
D t is the time interval. By combining this equation
with the formula for average velocity:
(1)
we
get an equation for accelerated motion:
D
s = vo t + 1/2 a t2
(3)
where
s is displacement and vo is the initial velocity. You
might recognize this from the Reaction Time Acitvity
where vo was zero because the meter stick was dropped
from rest and the acceleration was g = 9.8 m/s/s - the
acceleration due to gravity.
Also
if you look carefully at eqation (3) you can see that
if there is no acceleration, it becomes exactly the
same as equation (2)
All
three of these equations work if the motion is in one
dimension such as dropping a meter stick or throwing
a ball straight up. However, if you wish to look at
motion in two dimensions such as the flight of an arrow
or a fly ball you must remember one simple fact. Gravity
ONLY works vertically or in the y direction. Gravity
does not pull things sideways, it only pulls them down.
Therefore when motion is horizontal (x direction) and
vertical (y direction) at the same time we must consider
them seperately because gravity ONLY affects the y part
of the motion.
Separating
the x and y parts of an objects velocity is not difficult.
Consider a simple right triangle.
Using simple trigonometry we know that sinq= vy/v
or vy= v sinq and cosq= vx/v
or vx = vcosq. When an object is moving
at an angle q, we can consider the x and y dimensions
seperately and still use the equations above (1-3).
An
easy example:
Suppose a football is kicked at at 30o angle
with a velocity of 15 m/s and we need to know how high
it goes to see if it will clear the field goal.
| What
do you know? |
At
the beginning vy = 15 m/s sin 30o
= 7.5 m/s
and vx = 15 m/s cos 30o = 13
m/s
At the very top vy = 0 m/s because it stops
moving upward.
Using this we know that Dvy = -7.5 m/s
(the velocity decreases by 7.5 m/s)
For the whole trip a = -9.8 m/s/s
|
| What
are you trying to find? |
The height of the ball or the y displacement |
| Which
equations have this stuff in them? |
equation 1:
equation 3: D s = vo t + 1/2
a t2
Both equations also have time in them which we do
not know but we can use equation 1 to solve for time
and then plug that in equation 3. |
| Let's
solve the problem! |
-9.8 m/s/s = -7.5 m/s Dt
solving for Dt give Dt =.76 seconds
This is the time it takes the ball to reach the highest
point.
Now we can find the height using equation 3.
Ds = 7.5 m/s (.76s) + 1/2 (-9.8
m/s/s)(.76s)2
Solving for Ds gives Ds =2.9 m
Does the ball make the field goal? |
Find
the total velocity of a dart upon exiting your gun.
Some hints: If you only have a meterstick, what
things can you measure?
Which directions should you shoot your gun so that the
x or y velocity is zero?
Of the two directions you can shoot the gun, which one
gives values easy to measure with a meter stick?